Oblicz wartość każdego wyrażenia dla a = 1 i b = –1. Uzupełnij luki. I. a2 + 3ab = II. (a2 + 2b3) : 2 = III. (4ab – 5b) : (–2a) = IV. (–5a – 4) ∙ (3b + 1) =
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a=1
b=-1
podstawiamy za a i b podane liczby.
2*1 + 3*(1*[-1])=2+(-3)=-1
[2*1+2*(-1)*3] :2=2+(-2)*3 :2=0
4*1+(-1) - 5*(-1) : -2*1=3+5:2=4
-5*1-4*3(-1) + 1=-5-12 * -1 +1=18
I. a2 + 3ab =1*1+3*(1*-1)=1+3-3=4-3=1
II. (a2 + 2b3) : 2 = (1*1+2*(-1*-1*-1) :2= (1+2*-1):2=(1-2) : 2= -1: 2 = - 1/2 III. (4ab – 5b) : (–2a) = ( 4*(1*-1) - 5*-1): (-2*1)= (4*-1+5):(-2)=(-4+5):(-2)=1:(-2)= (-1/2) IV. (–5a – 4) ∙ (3b + 1) = (-5*1-4)*(3*-1+1)= (-5 - 4)*(-3+1)= (-9)* (-2) = 18
Miałam to zadanie :) Wszystko jest dobrze.