Oblicz :
w odpowiedziach pisze że ma wyjść 2
= √(2+√3)² -2*√(2+√3)*√(2-√3)+(√(2-√3))² =
= 2+√3 - 2*√[(2+√3)(2-√3)] + 2-√3 =
= 2 + √3 - 2* √(2²-(√3)²) + 2-√3 =
= 2+√3 - 2*√(4-3) + 2-√3 =
= 2 +√3 - 2*√1 + 2 - √3 =
=2 +√3 - 2*1 + 2 -√3 =
=2 - 2 + 2 -√3 + √3 =
= 0 + 2 + 0 =
= 2
(a - b)² = a²-2ab+b²
(a-b)(a+b) = a² - b²
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
= √(2+√3)² -2*√(2+√3)*√(2-√3)+(√(2-√3))² =
= 2+√3 - 2*√[(2+√3)(2-√3)] + 2-√3 =
= 2 + √3 - 2* √(2²-(√3)²) + 2-√3 =
= 2+√3 - 2*√(4-3) + 2-√3 =
= 2 +√3 - 2*√1 + 2 - √3 =
=2 +√3 - 2*1 + 2 -√3 =
=2 - 2 + 2 -√3 + √3 =
= 0 + 2 + 0 =
= 2
(a - b)² = a²-2ab+b²
(a-b)(a+b) = a² - b²