Oblicz, w jakim stosunku masowym są połączone pierwiastki we fruktozie.
mC6H12O6=72u+12u+96u=180u
mC : mH : mO = 72 : 12 : 96
mC : mH : mO = 6 : 1 : 8
MC6H12O6= 12u * 6 + 1u * 12 + 16u *6= 72u + 12u + 96u C6:H12:O6=72:12:96C:H:O=72:12:96 / :12C:H:O=6:1:8
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mC6H12O6=72u+12u+96u=180u
mC : mH : mO = 72 : 12 : 96
mC : mH : mO = 6 : 1 : 8
MC6H12O6= 12u * 6 + 1u * 12 + 16u *6= 72u + 12u + 96u
C6:H12:O6=72:12:96
C:H:O=72:12:96 / :12
C:H:O=6:1:8