metanolC - 12uH - 4*1=4uO - 16uC:H:O - 12:4:16 czyli3:1:4
Metanol-CH3OH
C-12u
H-4*1u=4u
O-16u
C:H:O-12:4:16
12:4:16/4
3:1:4
Stosunek masowy to - 3:1:4
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metanol
C - 12u
H - 4*1=4u
O - 16u
C:H:O - 12:4:16
czyli
3:1:4
Metanol-CH3OH
C-12u
H-4*1u=4u
O-16u
C:H:O-12:4:16
12:4:16/4
3:1:4
Stosunek masowy to - 3:1:4