oblicz w jakiej ilości bromku wapnia CaCr2 znajduje się 80g wapnia
bromek wapnia to CaBr2
M(CaBr2)=40+80*2=200g/mol
M(Ca)=40g/mol
200g/mol-40g/mol
x - 80g
x=(200g/mol*80g)/40g/mol
x=400g
:D
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bromek wapnia to CaBr2
M(CaBr2)=40+80*2=200g/mol
M(Ca)=40g/mol
200g/mol-40g/mol
x - 80g
x=(200g/mol*80g)/40g/mol
x=400g
:D