Oblicz w ilu gramach Ca3(PO4)znajduje sie:
a) 2g fosforu
b)1,5*10²³ atomów Ca
a) 2g fosforu
b)1,5*10²³ atomów Ca
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x=2
x=10g
1,5*10^23 at ca= xg ca3po4)2
3*6,02*10^23=310g
x=25,7g