oblicz sume Sn pierwszych n wyrazow ciagu geometrycznego an, jesli
a) a₁=½ , q=-1 , n=3
b) a₁=4 ,q=-½ ,n=6
1a]
S₃=a₁(1-q do potęgi n)/(1-q)=½(1+1)³:(1+1)=½×8:2=2
b]
S6=4(1+½)⁶:(1+½)=4×(3/2)⁵=4×243/32=243/8=30,375
Wzór na sumę:
a)
b)
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1a]
S₃=a₁(1-q do potęgi n)/(1-q)=½(1+1)³:(1+1)=½×8:2=2
b]
S6=4(1+½)⁶:(1+½)=4×(3/2)⁵=4×243/32=243/8=30,375
Wzór na sumę:
a)
b)