Oblicz sumę odwrotności rozwiązań równania:
72x²+963x+3=0
a=72
b=963
c=3
x₁, x₂ rozwiązania równaniea
wzory Viete'a: x₁+x₂ = -b/a x₁*x₂ = c/a
szukamy 1/x₁ + 1/x₂
1/x₁ + 1/x₂ =x₂/x₁x₂ + x₁/x₁x₂ = (x₁+x₂)/x₁x₂ =
= (-b/a) / (c/a) = -b/a * a/c = -b/c
czyli:
1/x₁ + 1/x₂ = -963/3 = -321
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72x²+963x+3=0
a=72
b=963
c=3
x₁, x₂ rozwiązania równaniea
wzory Viete'a: x₁+x₂ = -b/a x₁*x₂ = c/a
szukamy 1/x₁ + 1/x₂
1/x₁ + 1/x₂ =x₂/x₁x₂ + x₁/x₁x₂ = (x₁+x₂)/x₁x₂ =
= (-b/a) / (c/a) = -b/a * a/c = -b/c
czyli:
1/x₁ + 1/x₂ = -963/3 = -321