C12H22O1112*12=14422*1=2211*16=176144:22:176=72:11:88
Sacharoza: C₁₂H₂₂O₁₁
masa C = 12 * 12u =144umasa H = 22 * 1u = 22umasa O = 11 * 16u = 176u
Stosunek C : H : O = 144 : 22 : 176 = 72 : 11 : 88 (po skróceniu przez 2)
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C12H22O11
12*12=144
22*1=22
11*16=176
144:22:176=72:11:88
Sacharoza: C₁₂H₂₂O₁₁
masa C = 12 * 12u =144u
masa H = 22 * 1u = 22u
masa O = 11 * 16u = 176u
Stosunek C : H : O = 144 : 22 : 176 = 72 : 11 : 88 (po skróceniu przez 2)