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Ca : 2Br = 40u : ( 80 x 2)u = 40 : 160 = 1 : 4
b)
2Fe : 3O = (2 x 56)u : (3 x 16)u = 112 : 48 = 7 : 3
40u/2×80u = 40u/160u = 40/160 = 4/16 = 1/4 (jeden do czterech)
Fe₂O₃
2×56u/3×16u = 112u/48u =112/48 = 14/6 = 7/3 (siedem do trzech)
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