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Ca=40u
O= 16 x 2 = 32u
H= 2x1=2u
Ca:O:H=40:32:2=20:16:1
MCa=40
MO=16
MH=1
40:2*16:2*1 = 40:32:2 = 20:16:1
masa molowa
Ca= 40u
O(razy dwa)= 16 x 2 = 32u
H(razy dwa)= 2x1=2u
więc stosunek to:
Ca : O : H = 40 : 32 : 2
po skróceniu
20 : 16 : 1