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mKOH = 39u+16u+1u = 56u
mH2O = 2*1u+16u = 18u
1mol KOH = 56g
1mol H2O = 18g
10mol H2O = 180g
więc na 180g wody (10moli) przypada 56g KOH (1mol)
ms = 56g
mr = 56g+180g = 236g
cp = (ms/mr)*100% = 56g/236g * 100% ≈ 23,73%
Stężenie procentowe roztworu wynosi 23,73%.