Oblicz stężenie procentowe roztworu orzymanego po zmieszaniu
- 250g 20% NaOH oraz 10g NaOH
- 0,2 mola NaOH oraz 12 g wody
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1. 250 x 20% = 50g
m= 50g + 10g= 60g
Cp=60g/260g= ok 23%
2.m=0,2 mol x 40g/mol = 8g
Cp= 8g/20g x 100%= 40%