Oblicz stężenie molowe roztworu, który w objętości 1,2 zawiera 30 g KCL.
mKCl=1*39+35,5=74,5g
Cm=n/v
n=ms/Ms
n=30g/74,5g=0,40mola
V=1,2dm³
Cm=0,4mol/1,2dm³
cm=0,33mol/dm³
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
mKCl=1*39+35,5=74,5g
Cm=n/v
n=ms/Ms
n=30g/74,5g=0,40mola
V=1,2dm³
Cm=0,4mol/1,2dm³
cm=0,33mol/dm³