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= (2% * 1010 g/dm3) / (63 g/mol * 100%) = 0,3206 mol/dm3
Cm(H+) = Cm(HNO3) = 0,3206 mol/dm3, bo HNO3 jest mocnym elektrolitem
pH = -log[C(H+)] = -log(0,3206) = 0,5