Oblicz steżenie % roztworu otrzymanego przez rozpuszczenie 0,5 mola chlorku sodu w 100 g H2O .daje naj
M NaCl=58,5g/mol
58,5g NaCl------1mol
xg NaCl----------0,5mola
x = 29,25g NaCl
ms=29,25g
mw=100g
mr=ms+mw
mr=29,25g+100g =129,25g
Cp=?
Cp=ms*100%/mr
Cp=29,25*100/129,5
Cp = 22,6%
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M NaCl=58,5g/mol
58,5g NaCl------1mol
xg NaCl----------0,5mola
x = 29,25g NaCl
ms=29,25g
mw=100g
mr=ms+mw
mr=29,25g+100g =129,25g
Cp=?
Cp=ms*100%/mr
Cp=29,25*100/129,5
Cp = 22,6%