Oblicz sklad procentowy (procentmasowy) pierwiastków chemicznych w metanie.
m CH4 = mC + 4mH = 12 + 4 = 16
100 % -- 16
x --- 12
x = 75%
100% - 16
x ---- 4
x=25%
W metanie jest 75% węgla i 25% wodoru
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m CH4 = mC + 4mH = 12 + 4 = 16
100 % -- 16
x --- 12
x = 75%
100% - 16
x ---- 4
x=25%
W metanie jest 75% węgla i 25% wodoru