Oblicz skład procentowy związków: Al2(CO3)3 , Na2Cr2O7 , Fe2(SO4)3 , Al(OH)3
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Oblicz skład procentowy związków: Al2(CO3)3 , Na2Cr2O7 , Fe2(SO4)3 , Al(OH)3
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mAl2(CO3)3=54u+36u+144u=234u
%Al = (54/234)*100% = 23,1%
%C = (36/234)*100% = 15,4%
%O = (144/234)*100% = 61,5%
mNa2Cr2O7=46u+104+112u=262u
%Na = (46/262)*100% = 17,6%
%Cr = (104/262)*100% = 39,7%
%O = (112/262)*100% = 42,7%
mFe2(SO4)3=112u+96u+192u=400u
%Fe = (112/400)*100% = 28%
%S = (96/400)*100% = 24%
%O = (192/400)*100% = 48%
mAl(OH)3=27u+48u+3u=78u
%Al = (27/78)*100% = 34,7%
%O = (48/78)*100% = 61,5%
%H = (3/78)*100% = 3,8%