Question

Oblicz skład procentowy alkanu o 5 atomach węga w cząsteczce...

Answer 1

mC5H12=5*12u+12*1u=60u+12u=72u

 

%C = (60/72)*100% = 83,33%

%H = (12/72)*100% = 16,67%

Answer 2

Alkan: CnH2n+2

C5H12

 

C: 12*5=60 u

H: 12*1=12 u

             I

           72u

 

x= 60*100%/72=83% - węgiel

100%-83%=17% - wodór