Oblicz: (proszę krok po kroku)
1.
2.
3^ 0,5 log 3 16 = 3^ log 3 16^0,5 = 3 ^ log 3 4 = 4
27 ^ log 3 ( 2 - 1/3) = 27 ^ log 3 ( 5/3) = (3 ^ 3)^ log 3 ( 5/3) = 3 ^ [ 3 log 3 ( 5/3) ] =
= 3^ log 3 [ ( 5/3)^3] = 3 ^ log 3 ( 125/27) = 125/ 27
lub
27 ^ log 3 2 - 1/3 = 27 ^( - 1/3) * 27^ log 3 2 = ( 1/3) * ( 3^3)^log 3 2 = ( 1/3) * 3^ 3 log 3 2 =
= ( 1/3)* 3 ^log 3 2^3 = ( 1/3)* 3 ^ log 3 8 = ( 1/3) *8 = 8 / 3 = 2 2/3
rozw w zalaczniku,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
i jeszce tw a^(m-n)= a^m · a^(-n)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1.
3^ 0,5 log 3 16 = 3^ log 3 16^0,5 = 3 ^ log 3 4 = 4
2.
27 ^ log 3 ( 2 - 1/3) = 27 ^ log 3 ( 5/3) = (3 ^ 3)^ log 3 ( 5/3) = 3 ^ [ 3 log 3 ( 5/3) ] =
= 3^ log 3 [ ( 5/3)^3] = 3 ^ log 3 ( 125/27) = 125/ 27
lub
27 ^ log 3 2 - 1/3 = 27 ^( - 1/3) * 27^ log 3 2 = ( 1/3) * ( 3^3)^log 3 2 = ( 1/3) * 3^ 3 log 3 2 =
= ( 1/3)* 3 ^log 3 2^3 = ( 1/3)* 3 ^ log 3 8 = ( 1/3) *8 = 8 / 3 = 2 2/3
rozw w zalaczniku,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
i jeszce tw a^(m-n)= a^m · a^(-n)