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mC8H16=8*12u+16*1u=112u
96u---x%
112u-100%
x=85,71%C
100%-85,71=14,29%H
m C₈H₁₆ = 8 * 12u + 16 * 1u = 96u + 16u = 112u
112u ----------- 100%
96u ---------- x
x = 96u * 100% / 112u
x = 85,7% zawartość % węgla w oktenie
100% - 85,7% = 14,3% zawartość % wodoru w oktenie