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masa węgla=12u
masa wodoru=1u
mC3H8=3*12+8*1=36+8=44
44-100%
36-x
x=36*100/44
x=81,8%
mC₃H₈= 3 * 12u + 8 * 1u=44u
%C=36/44 * 100!=81,82%
%H=8/44 * 100%= 18,18%