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m=5kg W=?
s=h=4m
g=10m/s²
W = F × s
F = m × g
F = 5 × 10 = 50 [N]
[F] = [kg × m/s²] = [N]
W = 50 * 4 = 200 [J]
[W] = [kg × m/s² × m] = [kg × m²/s²] = [J]
Odp.: Kula wykona pracę o wartości 200J.
Dane :
m=5 kg
s czyli droga = 4m
W=F*s
F=mg
g=10 m/s
F=10*5=50 N(niutonów)
W=50*4=200
m=5 [kg]
droga = 4[m]
szukane
W=?
wzory
F=m x g
W=F x s
Rozwiązanie
F=m x g
siła= masa x przyspieszenie ziemskie (10 m/s)
F= 5 kg x 10 m/s0
F = 50 N [kg m / s]
W= F x s
praca[J] = siła[N] x droga [m]
W= 50[N] x 4[m]
W= 200 [J]