Oblicz pole trapezu równoramienego o podstawach 10cm i 14 cm oraz ramionach długosci 4 pierwiastków z 2 !!!!!!! pomocy !! HELP !!!
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14cm - 10cm = 4cm
4cm / 2 = 2cm
h² = (4√2cm)² - (2cm)²
h² = 32cm² - 4cm²
h² = 28cm²
h = √28 cm
h = 2√7cm
P = (a + b) * h / 2
P = (10cm + 14cm) * 2√7cm / 2
P = 24√7 cm²