Question

Oblicz pole sześciokąta foremnego wpisanego w okrąg o promieniu 8cm

2.Oblicz pole koła wpisanego w trójkąt foremny o boku 12cm

Answer 1

1]

r=8cm

a=8cm

p=6a²√3/4=6*8²√3/4=96√3cm²

2]

a= bok=12cm

h=wysokosc=a√3/2=12√3/2=6√3cm

⅓h=2√3cm

pole=π×(2√3)²=12πcm²

Answer 2

1. r = 8 cm

a = r

a = 6 cm

P =6(a^{2}\sqrt{3})/4

P = 6(6^{2}\sqrt{3})/4

P = 6*9\sqrt{3}

P = 54\sqrt{3}

 

 

2. a = 12 cm

a = r

r = 12 cm

P = \pi*r^{2}

P = \pi*12^{2}

P = 144 \pi