oblicz pole równoległoboku,którego bok ma 9,5 cm a wysokość poprowadzona do tego boku ma 7 cm
P = a*h
a = 9,5 cm
h = 7 cm
P = 9,5 * 7,0 = 66,5 cm^2
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P = a*h
a = 9,5 cm
h = 7 cm
P = 9,5 * 7,0 = 66,5 cm^2