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r dl. promienia wysepki
P1=πR² pole pow. jezdni razem z wyseoka
P2=πr² pole pow. wysepki
P1-P2 pole pow. jezdni
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a)
2R=24 [m]
R=12 [m]
2r=8 [m]
r=4 [m]
P1=12²π [m²]
P1=144π [m²]
P2=4²π
P2=16π
P1-P2=144π - 16π=128π
Odp. P1=144π
P2=16π
P1 - P2=128π wyniki w [m²]
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b)
R=4+6=10 m]
r=6 [m]
P1=100π
P2=36π
P1-P2=64π w [m²]
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c)
R=6+5=11
r=5
P1=121π
P2=25π
P1-P2=96π w [m²]