Question

Oblicz pole powierzchni calkowitej i objetosc stozka o promieniu podstawy r, wysokosci h i tworzacej l,gdy
r=9cm,h=40cm
2) r=20cm, l =29cm

Answer 1

Dane:
r=9cm,h=40cm

r²+h²=l²
9²+40²=l²
81+1600=l²
l²=1681
l=41cm

Pc=πr²+πrl
Pc=π*9²+π*9*41
Pc=81π+369π
Pc= 450π [cm²]

V=1/3*πr²*h
V=1/3*π*81*41
V=1107π [cm³]

2)
Dane:
r=20cm, l =29cm

r²+h²=l²
20²+h²=29²
h²=841-400
h²=441
h=21cm

Pc=πr²+πrl
Pc=π*20²+π*20*29
Pc=400π+580π
Pc=980π [cm²]

V=1/3*πr²*h
V=1/3*π*20²*21
V=1/3*π*400*21
V=2800π [cm³]