Question

Oblicz pole powierzchni całkowitej Pc i objętość V graniastosłupa prostego przedstawionego na rysunkach.

Answer 1

a ) Pp = a x h : 2

Pp = 20 x 15 : 2

Pp = 300 :2

Pp= 150

 

V = Pp x h

V = 150 x 15

V = 10

 

Pb1 = a x b

Pb1 = 20 x 15

Pb1= 300

 

Pb2 = 15 x 15

Pb = 225

 

Pc = 2 x Pp +2x Pb1 + Pb2

Pc = 300 + 600 + 225

Pc = 1125

 

b ) Pp = 12 x 10 : 2

Pp = 120 : 2

Pp = 60 

 

V = 60 x 15

V = 900

 

Pb = 3 x 15 x 10

Pb = 450

 

Pc = 2 x 60 + 450

Pc = 120 + 450

Pc = 570

 

c ) Pp = 8 x 4,5

Pp = 36

 

V = 36 x 11

V = 396

 

Pb = 8 x 5 +2 x (4,5 x 11) + 11 x 8

Pb= 40 + 99 + 88

Pb = 227

 

Pc = 2 x 36 + 227

Pc = 229