Oblicz pole powierzchni całkowitej i obietość sześcianu, którego długość wszystkich krawędzi jest równa 24 dm.
v= 24 dm do potegi 3=13824 dm3
Pc=6a do potegi2
6*24 do potegi 2=144 do potegi 2=20736
P = Pp · 2 + Pb
24dm : 12 = 2dm Pp = 2dm · 4 = 8dmPb = (2dm · 4) · 4 = 8dm · 4 = 32dmP = 8dm · 2 + 32dmP = 16dm² + 32dm = 48dm
V = a³V = 2dm · 2dm · 2dm = 8dm³
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v= 24 dm do potegi 3=13824 dm3
Pc=6a do potegi2
6*24 do potegi 2=144 do potegi 2=20736
P = Pp · 2 + Pb
24dm : 12 = 2dm
Pp = 2dm · 4 = 8dm
Pb = (2dm · 4) · 4 = 8dm · 4 = 32dm
P = 8dm · 2 + 32dm
P = 16dm² + 32dm = 48dm
V = a³
V = 2dm · 2dm · 2dm = 8dm³