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O (obwód kwadratu) = 4a
O=40dm
4a=40 /:4
a=10 dm
P - 10 8 10
P = 100 dm2
1 a = 1000 dm2
1a - 1000 dm2
xa - 100 dm2
1000x=100 /: 1000
x=100/1000
x=1/10
x=0,1
Odp. Pole kwadratu o obwodzie 40 dm wynosi 0,1 a.
O (obwód kwadratu) = 4a
O=40dm
4a=40 /:4
a=10 dm
P - 10 8 10
P = 100 dm2
1 a = 1000 dm2
1a - 1000 dm2
xa - 100 dm2
1000x=100 /: 1000
x=100/1000
x=1/10
x=0,1
Odp. Pole kwadratu o obwodzie 40 dm wynosi 0,1 a.