Oblicz pole koła opisanego na trójkącie równobocznym o boku 4cm.
h=a√3÷2
h=4√3÷2=2√3
r=⅓h
r=⅓2√3=⅔√3
P=π·r²
P=π·(⅔√3)²=1⅓·π≈4.2(j²)
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h=a√3÷2
h=4√3÷2=2√3
r=⅓h
r=⅓2√3=⅔√3
P=π·r²
P=π·(⅔√3)²=1⅓·π≈4.2(j²)