oblicz pole koła o obwodzie:
a)62,8m;
b)20 m .
PROSZE O DOKŁADNE OBLICZENIA
a
L=62,8 m
L=2 pi r
62,8 = 2 * 3,14 * r
62,8=6,28 *r / :6,28
r=10m
P= pi * r(do kwadratu)
P=pi*10m (do kwadratu)
P= 100 pi
b
20m =2 * pi * r / 2 * pi
20 m/ pi = r
P= pi *20m/pi
P=20m
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a
L=62,8 m
L=2 pi r
62,8 = 2 * 3,14 * r
62,8=6,28 *r / :6,28
r=10m
P= pi * r(do kwadratu)
P=pi*10m (do kwadratu)
P= 100 pi
b
L=2 pi r
20m =2 * pi * r / 2 * pi
20 m/ pi = r
P= pi *20m/pi
P=20m