oblicz pole koła o obwodzie 12 pi.
O = 2πr
12π = 2πr | /2
6π = πr | /π
r = 6
P = πr²
P = π6²
P = 36π j²
j - jednostka
2
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O = 2πr
12π = 2πr | /2
6π = πr | /π
r = 6
P = πr²
P = π6²
P = 36π j²
j - jednostka
2