Oblicz pole koła o obw.
a) 36 pi cm
b) l=8m
c) l=1l pi~
Oblicz pole pierścienia
a)R=10 r=2
b)R= 9 r=3 pi~ 3,1
a)l=36π
2πr=36π /:2π
r=18
P=πr²=18²π=324π cm²
b)l=8m
2πr=8 /:2π
r=4/π
P=(4/π)²·π=16/π² ·π =16/π m²
c)l=1l π
2πr=1l /:2π
r=1/2π
P=(1/2π)²π =1/4π² ·π =1/4π l
zad2
R=10 i r=2
a)P=π(R²-r²)=π(10²-2²)=π(100-4)=96π j²
b)R=9 i r=3
P=π(9²-3²)=π(81-9)=72πj²
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a)l=36π
2πr=36π /:2π
r=18
P=πr²=18²π=324π cm²
b)l=8m
2πr=8 /:2π
r=4/π
P=(4/π)²·π=16/π² ·π =16/π m²
c)l=1l π
2πr=1l /:2π
r=1/2π
P=(1/2π)²π =1/4π² ·π =1/4π l
zad2
R=10 i r=2
a)P=π(R²-r²)=π(10²-2²)=π(100-4)=96π j²
b)R=9 i r=3
P=π(9²-3²)=π(81-9)=72πj²