oblicz pole koła, którego obwód jest równy:
a) 7,536 m
b)15,7 cm
c)39,25 dm
d) 117, 75 dm
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a) 2r=7,536m
2*3,14*r=7,536
6,28r=7,536 /6,28
r=1,2m
b)2r=15,7cm
2*,3,14*r=15,7
6,28r=15,7/6,28
r=2,5 cm
c)2r=39,25 dm
2*3,14*r=39,25
6,28r=39,25 /6,28
r=6,25 dm
d)2r=117,75 dm
2*3,14*r=117,75
6,28r=117,75 /6,28
r=18,75 dm
2πr=O
P=πr²
a)7,536 m=2πr
7,536/2π=r
P=π*(7,536/2π)²
P=π*56,791296/4π²
P=14,197824/π m²
b)15,7 cm
15,7/2π=r
P=π*(15,7/2π)²
P=π*246,49/4π²
P=61,6225/π
c)39,25 dm
39,25/2π=r
P=π*(39,25/2π)²
P=π*1540,5625/4π²
P=385,140625/π
d)117,75 dm
117,75/2π=r
P=π*(117,25/2π)²
P=π*13747,5625/4π²
P=3436,89062/π