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p=e*f/2
e=12cm
f=16cm
P=16cm*12cm/2
P=96cm²
O=4a ,
a obliczamy z pitagorasa
a=?
b=8
c=6
b²+c²=a²
8²+6²=a²
64+36=a²
100=a² / √
a=10
O=4*10
O=40cm
d1, d2 = 16cm i 12cm
P = d1 × d2 ÷ 2
P = 16 × 12 ÷ 2 = 16 × 6 = 96cm²
h = 80% × 12cm = 4/5 × 12cm = 9.6cm
P = a × h
a = P / h
a = 96cm² / 9.6cm = 10cm
Obw = 4 × a = 40cm
Odp. Pole tego rombu to 96cm², a obwód jest równy 40cm.