Question

Oblicz pole i objetosc .

a)graniastosłupa prawidłowego czworokatnego

b)graniastołupa o podstawie trojkata prostokatnego

c)graniastosłupa prawidlowego dwunastokatnego

Wymiary do a i c to a=8cm H=25cm

Wymiary do b to a=8cm b=11cm H=25cm

Z gory dzieki pzdro;p

Answer 1

a) P=2a^2+4aH=128+4*200=928 cm^2

V: a^2*H=64*25=1600 cm^3

b) P=2+aH+bH+cH

c=

P=88+200+275+25=563+25903,04 cm^2

V=ab/2*H=88/2*25=1100 cm^3

c) P=2[3a^2(2+]+12aH=2[3*64(2+]+12*8*25=2(384+192)+2400=768+2400+384=3168+384cm^2

V=Pp*H=(384+192)*25=9600+4800 cm^3

Pozdrawiam :D

Answer 2

a)

a = 8 cm

H = 25 cm 

 

P = 2a^2 + 4a* H =2 *(8cm)^2 + 4 * 25cm = 128cm2 + 100cm2

P = 228cm2

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V = Pp * H

V = a^2 *  = (8cm)2 * 25cm

V = 1600 cm3

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b)

a = 8cm

b = 11 cm 

H = 25cm 

 

c^2 = a^2 + b^2 = 8^2 + 11^2 = 185

c = V185 = 13,6cm

 

P = 2 *1/2 a* b + H(a+b+c)

P = 8cm *11cm + 25cm(8+11+13,6)cm  =(88+815)cm2

P = 903 cm2

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V = Pp * H

V = 1/2 * a * b * H = 1/2 * 8cm * 11cm * 25cm

V = 1100 cm3

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c)

a = 8 cm

H = 25 cm

Wzór na pole dwunastokąta:

P = 3a^2(2+V3)

 

Pc = 2 *3a^2(2+V3) +12a *H  = 2 *3 *(8cm)^2*(2+V 3) +12 * 8cm * 25cm  =

= 384(2+V3)cm2 + 2400cm2 = (768+384V3+2400 = (3168+384V3)cm2

Pc = 32(99+12V3)cm2

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V = Pp * H

V = 3a^2(2+V3) * H = 3 *(8cm)^2 *3+V3) * 25cm

V = 4800(2+V3) cm3

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