oblicz pole calkowite i przekatna prostopadloscianu o wymiarach 2x4x5
a=2
b=4
c=5
Pc=2ab+2(a+b)*c
Pc=2*4+2(2+4)*5=8+10*6=8+60
Pc=68 [j^2]
----
d=√(a^2+b^2+c^2)
d=√(2^2+4^2+5^2)=√(4+16+25)=√45=√(9*5)
d=3√5 [j]
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a=2
b=4
c=5
Pc=2ab+2(a+b)*c
Pc=2*4+2(2+4)*5=8+10*6=8+60
Pc=68 [j^2]
----
d=√(a^2+b^2+c^2)
d=√(2^2+4^2+5^2)=√(4+16+25)=√45=√(9*5)
d=3√5 [j]