Question

oblicz pola i obwody narysowanych figur a)rombu b) trapezu równoramiennego​

Answer 1

Odpowiedź:

a )  x² + (3 √5)² = 9²

x² = 81 - 9*5 = 81 - 45 = 36

x = [tex]\sqrt{36} = 6[/tex]

więc

Pole  rombu

e = 2*3√5 = 6√5

f = 2*6 = 12

P = 0,5 e*f = 0,5*6√5*12 = 36√5 [ j² ]

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Obwód

L = 4*9 = 36

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z.3

h² + 6² = 10²

h² = 100 - 36 = 64

h = [tex]\sqrt{64} = 8[/tex]

b = 15

a = 6 + 15 + 6 = 27

Pole trapezu

P = 0,5*( a + b )*h = 0,5*( 27 + 15)*8 = 21*8 = 168  [ j² ]

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Obwód

L = 2*10 + 2*6 + 2*15 = 20 + 12 + 30 = 62

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Szczegółowe wyjaśnienie: