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f(x)=-cos²x+cosx+1
f'(x)=sin2x-sinx
f'(x)=0
sin2x-sinx=0
sinx=t
t²-t=0
t(t-1)=0
t=0 ∨ t=1
sinx=0 ∨ sinx=1
x=kπ v x=π/2+2kπ