oblicz ( pierwiastek z 3 + pierwiastek 2) do kwadratu -(pierwiastek z 5+ 2)=
proszę mi to rozwiązać teraz
(√3+√2)² - (√5 + 2) = (√3)² + 2*√3*√2 + (√2)² - √5 - 2 =
= 3 + 2√6+2- √5 - 2 = 3 + 2√6 - √5
(a+b)² = a²+2ab + b²
(sqrt3+sqrt2)^2-(sqrt5+2)=(3+2sqrt3*sqrt2+2)-sqrt5-2=3+2sqrt6-sqrt5
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(√3+√2)² - (√5 + 2) = (√3)² + 2*√3*√2 + (√2)² - √5 - 2 =
= 3 + 2√6+2- √5 - 2 = 3 + 2√6 - √5
(a+b)² = a²+2ab + b²
(sqrt3+sqrt2)^2-(sqrt5+2)=(3+2sqrt3*sqrt2+2)-sqrt5-2=3+2sqrt6-sqrt5