Oblicz, pamiętając o kolejności wykonywania działań i skracaniu ułamków. a) ( - + ) x 3 = b)(

Krzysiek2002 @Krzysiek2002

January 2019 1 10 Report

Oblicz, pamiętając o kolejności wykonywania działań i skracaniu ułamków.
a) ( $\frac{5}{3}$ - $\frac{1}{3}$ + $\frac{7}{3}$ ) x 3 =
b)( $\frac{11}{2}$ - $\frac{5}{2}$ + $\frac{15}{2}$ ) x 2 =
c) 3 $\frac{2}{3}$ + 3 x 1 $\frac{1}{3}$ =
d) 3 $\frac{1}{4}$ x 4 - 2 $\frac{3}{4}$ =
e) 2 $\frac{1}{5}$ x 5 - 4 $\frac{2}{5}$ + 1 $\frac{1}{5}$ =
f) 7 $\frac{1}{2}$ - 3 + 2 x $\frac{3}{4}$ =
g) 2 $\frac{1}{2}$ x 3 + 4 x 1 $\frac{1}{2}$ =
h) 2 $\frac{1}{4}$ x 2 + 3 $\frac{3}{4}$ =
i) 9 - 1 $\frac{3}{5}$ x 4 =

krysta $a) \\\\( \frac{5}{3} - \frac{1}{3} + \frac{7}{3} ) * 3 =( \frac{4}{3} + \frac{7}{3} ) * 3 = \frac{11}{3}*3=11$

$b)\\\\( \frac{11}{2} - \frac{5}{2} + \frac{15}{2} ) * 2 =( \frac{6}{2} + \frac{15}{2} ) * 2 =\frac{21}{2}*2=21$

$c)\\\\ 3 \frac{2}{3} + 3 * 1 \frac{1}{3} = 3 \frac{2}{3} + 3 * \frac{4}{3} = 3 \frac{2}{3}+4=7\frac{2}{3}$

$d)\\\\ 3 \frac{1}{4} * 4 - 2 \frac{3}{4} = \frac{13}{4} * 4 - 2 \frac{3}{4} =13- 2 \frac{3}{4} = 10\frac{1}{4}$

$e)\\\\2 \frac{1}{5} * 5 - 4 \frac{2}{5} + 1 \frac{1}{5} = \frac{11}{5} * 5 - 4 \frac{2}{5} + 1 \frac{1}{5} =11- 4 \frac{2}{5} + 1 \frac{1}{5} = 6\frac{3}{5} +1\frac{1}{5} = 7\frac{4}{5}$

$f)\\\\ 7 \frac{1}{2} - 3 + 2 * \frac{3}{4} =7 \frac{1}{2} - 3 + \frac{3}{2 } =4 \frac{1}{2} + \frac{3}{2} = 4\frac{4}{2}=6$

$g )\\\\ 2 \frac{1}{2} * 3 + 4 * 1 \frac{1}{2} = \frac{5}{2} * 3 + 4 * \frac{3}{2} =\frac{15}{2} + \frac{12}{2} =\frac{27}{2}=13\frac{1}{2}$

$h)\\\\ 2 \frac{1}{4} * 2 + 3 \frac{3}{4} = \frac{9}{4} *2 + 3 \frac{3}{4} = \frac{9}{4} *2 + 3 \frac{3}{4} =4\frac{2}{4} + 3 \frac{3}{4} =7\frac{5}{4}=8\frac{1}{4}$

$i)\\\\ 9 - 1 \frac{3}{5}* 4 = 9 - \frac{8}{5} * 4 = 9 - \frac{32}{5} = 9 - 6 \frac{ 2}{5}=2\frac{3}{5}$

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