Oblicz obwód trójkąta równobocznego, wiedzc, ze jego wysokosc wynosi:
B)24% z 8 dm
plis na jutro
\frac{24}{100}\ *\ \frac{25}{3}\ \sqrt{3}\ =\ \frac{600}{300}\ \sqrt{3}\ =\ 2\ \sqrt{3} dmh\ =\ \frac{a \sqrt{3}}{2}2h = a \sqrt{3}
\frac{2h}{\sqrt{3}} = a\frac{2h}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = a\frac{2h\sqrt{3}}{3} = aa = \frac{4*3}{3}a = 4 dm\sqrt{x}Obw.: 4 + 4 + 4 = 12 dm
zad 24%=0,24
8⅓√3dm=(25√3)/3dm·24%=(25√3)/3·0,24=600√3/300=2√3---wysokosc h Δ
h=(a√3):2
2√3=(a√3)/2
a√3=2·2√3=4√3
a=4√3:√3=4
a=4dm-->dlugosc boku Δ
Obwod O=3·4=12dm
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\frac{24}{100}\ *\ \frac{25}{3}\ \sqrt{3}\ =\ \frac{600}{300}\ \sqrt{3}\ =\ 2\ \sqrt{3} dm
h\ =\ \frac{a \sqrt{3}}{2}
2h = a \sqrt{3}
\frac{2h}{\sqrt{3}} = a
\frac{2h}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = a
\frac{2h\sqrt{3}}{3} = a
a = \frac{4*3}{3}
a = 4 dm
\sqrt{x}
Obw.: 4 + 4 + 4 = 12 dm
zad 24%=0,24
8⅓√3dm=(25√3)/3dm·24%=(25√3)/3·0,24=600√3/300=2√3---wysokosc h Δ
h=(a√3):2
2√3=(a√3)/2
a√3=2·2√3=4√3
a=4√3:√3=4
a=4dm-->dlugosc boku Δ
Obwod O=3·4=12dm