Oblicz obw. trójkąta DCE, jeśli:
D(1,2) ; C(-3,6) ; E(-2,-5)
DC=√[(1+3)²+(2-6)²]=√[16+16]=√32=4√2
DE=√[(1+2)²+(2+5)²]=√[9+49]=√58
CE=√[(-3+2)²+(6+5)²]=√[1+121]=√122
obwód=4√2+√58+√122
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DC=√[(1+3)²+(2-6)²]=√[16+16]=√32=4√2
DE=√[(1+2)²+(2+5)²]=√[9+49]=√58
CE=√[(-3+2)²+(6+5)²]=√[1+121]=√122
obwód=4√2+√58+√122