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V = Pp * H
Pp = ah/2
Pp = 6*5 / 2
Pp = 15 j^2
V = 15 * 7
V = 105 j^3
b)
V = Pp * H
Wyliczamy h z tw. Pitagorasa
5^2 - 3^2 = h^2
h^2 = 25 - 9
h^2 = 16
h = 4
Pp = ah/2
Pp = 4*6/2
Pp = 12 j^2
V = 12 * 8
V = 96 j^3
c)
V = PpH
Pole podstawy policzymy jako sumę dwóch trójkątów
Pp1 = 7 * 4 / 2
Pp1 = 14 j^2
Pp2 = 8 * 1 / 2
Pp2 = 4 j^2
Pp = Pp1 + Pp2
Pp = 18 j^2
V = 18 * 6
V = 108 j^3