Question

Oblicz objętość stożków przedstawionych na rysunkach

pilne

Answer 1

1.
V = 1/3πr²H
l = 10√2
śr = 10
r = 5
obliczam H z tw. Pitagorasa
H²+5² = (10√2)²
H² = 100*2-25
H² = 200-25
H² = 175
H = √175 = √25*7 = 5√7
V = 1/3πr²H
V = 1/3π*5²*5√7
V = (125/3)π√7

2.
V = 1/3πr²H
l = 10
r = 5
obliczam H z tw. Pitagorasa
H²+5² = 10²
H² = 100-25
H² = 75
H = √75 = √25*3 = 5√3
V = 1/3πr²H
V = 1/3π*5²*5√3
V = (125/3)π√3