Oblicz objętość 3,5 molowego roztworu HNO₃ wiedząc, że zawiera 12,6g substancji.
PILNE!
V=? Cm=3,5mol/dm3 ms=12,6g
MHNO3=1+14+3*16u=63g/mol
Cm=n/V
V=n/Cm
n=m/M
n=12,6g/63g/mol
n=0,2mol
V=0,2mol/3,5mol/dm3
V=0,057dm3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
V=? Cm=3,5mol/dm3 ms=12,6g
MHNO3=1+14+3*16u=63g/mol
Cm=n/V
V=n/Cm
n=m/M
n=12,6g/63g/mol
n=0,2mol
V=0,2mol/3,5mol/dm3
V=0,057dm3