Oblicz objetoscnstozka o promieniu podstawy r ,wysokosci h i tworzacej l jezeli:r=0,4dmh=cm
PILNE !!!!!!!!!POMOZCIE
r=0,4dm=4cm
h= 6cm
l=√(4²+6²]=√[16+36]=√52=2√13cm
Pp=πr²=π×4²=16π
v=⅓Pph=⅓×16π×6=32π cm³
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r=0,4dm=4cm
h= 6cm
l=√(4²+6²]=√[16+36]=√52=2√13cm
Pp=πr²=π×4²=16π
v=⅓Pph=⅓×16π×6=32π cm³