Oblicz objetosc i pole powierzchni calkowitej stozka o srednicy podstawy rownej 6cm i wysokosci 12cm .Prosze o rozwiazanie z wzorami
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d = 6 cm
r = 3 cm
V = ⅓ * pp*h
V = ⅓ * 3² * 12
V = 36
3² + 12² = l²
9 + 144 = l²
l =√153
l≈ 12,37
P = Pp + Pb
P = πr² + πrl
P = π3² + π*3*12,37
P = 9π + 37,11π
p = 46,11π
P = 46,11 * 3,14
P = 144,78